Some water by the following reaction is mass production?
I carried through the combustion of ammonia gas ivestigation AM: 4NH3 + 5O2 "4NO + 6H2O reaction gas is 25.00 degrees 75 degrees C in the first After reaction of 5.400 over a steel chamber pressure is monitored by the current. Of oxygen in the chamber, the initial 21.250 16.500 ATM ATM ammonia added in slight excess of () Is filled with. This one just stumps me.
The first mole of ammonia: NH3 of PV = (21.250 ATM term) (5.400L) = n (0.08206 L-atm/mol-K) (298.15K) found that NRT = 4.690 Warts ----------- --------- Now, because They respond: 4NH3 + 5O2 "4NO + 6H2O? Drive water drive water = 6 @ 4.690 mall NH3 / 4 drive water NH3 = 7.0352 Mole ------------------- - 7.0352 Mall Water @ 18.015 g / drive = 126.7395 grams of water is the answer (4 Sig Fig): 126.7 grams of water
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